JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
In an \(n-p-n\) common emitter (\(CE\)) transistor the collector current changes from \(5\,mA\) to \(16\,mA\) for the change in base current from \(100\,\mu A\) and \(200\,\mu A\), respectively. The current gain of transistor is
- A \(110\)
- B \(0.9\)
- C \(210\)
- D \(9\)
Answer & Solution
Correct Answer
(A) \(110\)
Step-by-step Solution
Detailed explanation
Current gain in common emitter transistor \(\beta=\frac{\Delta I _{ C }}{\Delta I _{ B }}=\frac{16 mA -5 mA }{200 \mu A -100 \mu A }=\frac{11 mA }{100 \mu A }=110\)
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