JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2022
- Medium
- MCQ
A transverse wave is represented by \(y=2 \sin\) \((\omega t - kx ) cm\). The value of wavelength (in \(cm\) ) for which the wave velocity becomes equal to the maximum particle velocity, will be.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(4 \pi\)
Step-by-step Solution
Detailed explanation
\(y=2 \sin (\omega t-k x)\)
Maximum particle velocity \(= A \omega\)
Wave velocity \(=\frac{\omega}{ k }\)
\(\frac{\omega}{ k }= A \omega\)
\(k =\frac{1}{ A }=\frac{2 \pi}{\lambda}\)
\(\lambda =2 \pi A\)
\(=4 \pi\,cm\)
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