JEE Mains · Physics · STD 11 - 14. waves and sound
A transverse wave is represented by \(y=2 \sin\) \((\omega t - kx ) cm\). The value of wavelength (in \(cm\) ) for which the wave velocity becomes equal to the maximum particle velocity, will be.
- A \(4 \pi\)
- B \(2 \pi\)
- C \(\pi\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(4 \pi\)
Step-by-step Solution
Detailed explanation
\(y=2 \sin (\omega t-k x)\) Maximum particle velocity \(= A \omega\) Wave velocity \(=\frac{\omega}{ k }\) \(\frac{\omega}{ k }= A \omega\) \(k =\frac{1}{ A }=\frac{2 \pi}{\lambda}\) \(\lambda =2 \pi A\) \(=4 \pi\,cm\)
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