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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2022
  • Medium
  • MCQ

A transverse wave is represented by \(y=2 \sin\) \((\omega t - kx ) cm\). The value of wavelength (in \(cm\) ) for which the wave velocity becomes equal to the maximum particle velocity, will be.

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Answer & Solution

Correct Answer

(A) \(4 \pi\)

Step-by-step Solution

Detailed explanation

\(y=2 \sin (\omega t-k x)\)

Maximum particle velocity \(= A \omega\)

Wave velocity \(=\frac{\omega}{ k }\)

\(\frac{\omega}{ k }= A \omega\)

\(k =\frac{1}{ A }=\frac{2 \pi}{\lambda}\)

\(\lambda =2 \pi A\)

\(=4 \pi\,cm\)

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