JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
If each diode has a forward bias resistance of \(25\,\Omega\) in the below circuit,Which of the following options is correct:
- A \(\frac{ I _3}{ I _4}=1\)
- B \(\frac{ I _2}{ I _3}=1\)
- C \(\frac{I_1}{I_2}=1\)
- D \(\frac{I_1}{I_2}=2\)
Answer & Solution
Correct Answer
(D) \(\frac{I_1}{I_2}=2\)
Step-by-step Solution
Detailed explanation
\(R _{ eq }=\frac{150 \times 150}{300}+25=100 \Omega\) \(I _1=\frac{5}{10}=0.05\,A\) \(I _2= I _4=\frac{0.05}{2}=0.025\,A\) \(\frac{ I _1}{ I _2}=2\)
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