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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2019
  • Easy
  • Numerical

A string is clamed at both the ends and it is vibrating in its \(4^{th}\) harmonic. The equation of the stationary wave is \(Y =0.3\,sin\,(0.157\,x) \,cos\,(200\pi t)\). The length of the string is ..... \(m\) (all quantities are in \(SI\) units)

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Answer & Solution

Correct Answer

(B) \(80\)

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Detailed explanation

\(4^{\text {th }}\) harmonic

\(4 \frac{\lambda}{2}=\ell \quad ; 2 \lambda=\ell\)

From equation \(\frac{2 \pi}{\lambda}=0.157\)

\(\lambda=40 ; \quad \ell=2 \lambda=80 \mathrm{m}\)

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