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JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion

The position vector of a particle related to time \(t\) is given by \(\overrightarrow{ r }=\left(10 t \hat{ i }+15 t ^2 \hat{ j }+7 \hat{ k }\right) m\) The direction of net force experienced by the particle is

  1. A Positive \(y\)-axis
  2. B Positive \(x\)-axis
  3. C Positive \(z-\)axis
  4. D In \(x-y\) plane
Verified Solution

Answer & Solution

Correct Answer

(A) Positive \(y\)-axis

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ r }=10 t \hat{ i }+15 t ^2 \hat{ j }+7 \hat{ k }\) \(\overrightarrow{ v }=10 \hat{ i }+30 t \hat{ j }\) \(\overrightarrow{ a }=30 \hat{ j }\) So Net force is along \(+ y\) direction
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