JEE Mains · Physics · STD 11 - Newtons laws of motion
- JEE Mains 2023
- Medium
- MCQ
The position vector of a particle related to time \(t\) is given by \(\overrightarrow{ r }=\left(10 t \hat{ i }+15 t ^2 \hat{ j }+7 \hat{ k }\right) m\) The direction of net force experienced by the particle is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) Positive \(y\)-axis
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ r }=10 t \hat{ i }+15 t ^2 \hat{ j }+7 \hat{ k }\)
\(\overrightarrow{ v }=10 \hat{ i }+30 t \hat{ j }\)
\(\overrightarrow{ a }=30 \hat{ j }\)
So Net force is along \(+ y\) direction
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