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JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Four particles \(A, B, C\) and \(D\) with masses \(m_A=m, m_B=2m, m_C=3m\) and \(m_D=4m\) are at the corners of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the centre of mass of the particles is
- A \(\frac{a}{5}\,\left( {\hat i - \hat j} \right)\)
- B Zero
- C \(\frac{a}{5}\,\left( {\hat i + \hat j} \right)\)
- D \(a\left( {\hat i + \hat j} \right)\)
Answer & Solution
Correct Answer
(A) \(\frac{a}{5}\,\left( {\hat i - \hat j} \right)\)
Step-by-step Solution
Detailed explanation
\({\overrightarrow a _A} = - a\hat i\,\,\,\,\,\,\,\,\,\,;\,\,\,\,\,\,\,\,\,\,\,\,{\overrightarrow a _S} = a\hat j\) \({\overrightarrow a _C} = a\hat i\,\,\,\,\,\,\,\,\,\,\,\,\,;\,\,\,\,\,\,\,\,\,\,\,\,{\overrightarrow a _D} = - a\hat j\)…
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