JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
If \(10^{22}\) gas molecules each of mass \(10^{-26}\, kg\) collide with a surface (perpendicular to it)elastically per second over an area \(1\, m^2\) with a speed \(10^4\,m/s\), the pressure exerted by the gas molecules will be of the order of
- A \({10^8}\,\frac{N}{{{m^2}}}\)
- B \({10^3}\,\frac{N}{{{m^2}}}\)
- C \({10^4}\,\frac{N}{{{m^2}}}\)
- D None of this
Answer & Solution
Correct Answer
(D) None of this
Step-by-step Solution
Detailed explanation
Pressure is defined as normal force per unit area. Force is calculated as change in \( momentum/time.\) By this answer is \(2 \mathrm{N} / \mathrm{m}^{2}\) None of the option matches so this question must be Bonus. Detailed solution is as following:…
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