JEE Mains · Physics · STD 12 - 10. Wave optics
In a double slit experiment, at a certain point on the screen the path difference between the two interfering waves is \(\frac{1}{8} ^{th}\) of a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is
- A \(0.568\)
- B \(0.672\)
- C \(0.760\)
- D \(0.583\)
Answer & Solution
Correct Answer
(D) \(0.583\)
Step-by-step Solution
Detailed explanation
\(I=I_{0} \cos ^{2}\left(\frac{\Delta \phi}{2}\right)\) \(\frac{I}{I_{0}}=\cos ^{2}\left(\frac{\Delta \phi}{2}\right)\) \(\frac{I}{I_{0}}=\cos ^{2}\left(\frac{\frac{2 \pi}{\lambda} \times \frac{\lambda}{8}}{2}\right)\)…
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