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JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young's double slit experiment \(15\) fringes are observed on a small portion of the screen when light of wavelength \(500 \;\mathrm{nm}\) is used. Ten fringes are observed on the same section of the screen when another light source of wavelength \(\lambda\) is used. Then the value of \(\lambda\) is (in \(\mathrm{nm})\)
- A \(750\)
- B \(600\)
- C \(625\)
- D \(700\)
Answer & Solution
Correct Answer
(A) \(750\)
Step-by-step Solution
Detailed explanation
The length of the screen used portion for \(15\) fringes, and also for ten fringes \(15 \times 500 \times \frac{D}{\lambda}=10 \times \frac{\lambda D}{\lambda}\) \(15 \times 50=\lambda\) \(\lambda=750 \mathrm{nm}\)
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