JEE Mains · Physics · STD 12 - 3. current electricity
In the experiment of \(Ohm's law,\) a potential difference of \(5.0\, V\) is applied across the end of a conductor of length \(10.0\, cm\) and diameter of \(5.00\, mm .\) The measured current in the conductor is \(2.00\, A\). The maximum permissible percentage error in the resistivity of the conductor is
- A \(3.9\)
- B \(8.4\)
- C \(7.5\)
- D \(3.0\)
Answer & Solution
Correct Answer
(A) \(3.9\)
Step-by-step Solution
Detailed explanation
\(R =\frac{\rho \ell}{ A }=\frac{ V }{ I }\) \(\rho=\frac{ AV }{ I \ell}=\frac{\pi d ^{2} V }{4 I \ell} \quad\left( A =\frac{\pi d ^{2}}{4}\right)\)…
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