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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2022
  • Easy
  • MCQ

If \(Z=\frac{A^{2} B^{3}}{C^{4}}\), then the relative error in \(Z\) will be

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Answer & Solution

Correct Answer

(C) \(\frac{2 \Delta A }{ A }+\frac{3 \Delta B }{ B }+\frac{4 \Delta C }{ C }\)

Step-by-step Solution

Detailed explanation

\(Z=\frac{A^{2} B^{3}}{C^{4}}\)

In case of error

\(\frac{ dZ }{ Z }=\frac{2 d A}{ A }+\frac{3 dB }{ B }+\frac{4 dC }{ C }\)

\(\frac{\Delta Z }{ Z }=\frac{2 \Delta A }{ A }+\frac{3 \Delta B }{ B }+\frac{4 \Delta C }{ C }\)

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