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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2021
  • Hard
  • Numerical

A prism of refractive index \(n_{1}\) and another prism of refractive index \(n_{2}\) are stuck together (as shown in the figure). \(n_{1}\) and \(n_{2}\) depend on \(\lambda\), the wavelength of light, according to the relation \({n}_{1}=1.2+\frac{10.8 \times 10^{-14}}{\lambda^{2}} \text { and } {n}_{2}=1.45+\frac{1.8 \times 10^{-14}}{\lambda^{2}}\) The wavelength for which rays incident at any angle on the interface \(B C\) pass through without bending at that interface will be \(....\,nm.\)

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Answer & Solution

Correct Answer

(B) \(600\)

Step-by-step Solution

Detailed explanation

For no deviation, \(n_{1}=n_{2}\)

\(1.2+\frac{10.8 \times 10^{-14}}{\lambda^{2}} =1.45+\frac{1.8 \times 10^{-14}}{\lambda^{2}}\)

\(0.25 =\frac{9 \times 10^{-14}}{\lambda^{2}}\)

\(\lambda^{2} =\frac{9 \times 10^{-14}}{0.25}\)

\(\lambda =\frac{3}{5} \times 10^{-6}\)

\(\lambda =6 \times 10^{-7} m\)

\(\lambda =600 nm\)

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