JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
If the maximum value of accelerating potential provided by a ratio frequency oscillator is \(12\, {kV}\). The number of revolution made by a proton in a cyclotron to achieve one sixth of the speed of light is ....... . \(\left[{m}_{{p}}=1.67 \times 10^{-27} {kg}, {e}=1.6 \times 10^{-19} {C},\right.\) Speed of light \(\left.=3 \times 10^{8} {m} / {s}\right]\)
- A \(343\)
- B \(345\)
- C \(543\)
- D \(534\)
Answer & Solution
Correct Answer
(C) \(543\)
Step-by-step Solution
Detailed explanation
\({V}=12\, {kV}\) Number of revolution \(={n}\) \({n}\left[2 \times {q}_{{P}} \times {V}\right]=\frac{1}{2} {m}_{{p}} \times {v}_{{P}}^{2}\) \({n}\left[2 \times 1.6 \times 10^{-19} \times 12 \times 10^{3}\right.\)…
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