JEE Mains · Physics · STD 11 - 9.2 surface tension
If two glass plates have water between them and are separated by very small distance ( see figure), it is very difficult to pull them apart. It is because the water in between forms cylindrical surface on the side that gives rise to lower pressure in the water in comparison to atmosphere. If the radius of the cylindrical surface is \(R\) and surface tension of water is \(T\) then the pressure in water between the plates is lower by
- A \(\frac {T}{R}\)
- B \(\frac {4T}{R}\)
- C \(\frac {T}{4R}\)
- D \(\frac {2T}{R}\)
Answer & Solution
Correct Answer
(D) \(\frac {2T}{R}\)
Step-by-step Solution
Detailed explanation
\(d=2 R \cos \theta\) Pressure difference across a double curvature film \(\Delta P=2 T\left(\frac{1}{R_{1}}+\frac{1}{R_{2}}\right)\) \(\because \quad R_{1}=R\) and \(R_{2}=\infty\) \(\Delta P=2 T\left(\frac{1}{R}+\frac{1}{\infty}\right)\) \(\Delta P=\frac{2T}{R}\)
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