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JEE Mains · Physics · STD 11 - 9.2 surface tension

When an air bubble of radius \(r\) rises from the bottom to the surface of a lake, its radius becomes \(\frac{{5r}}{4}\).Taking the atmospheric pressure to be equal to \(10\,m\) height of water column, the depth of the lake would approximately be ....... \(m\) (ignore the surface tension and the effect of temperature)

  1. A \(10.5\)
  2. B \(8.7\)
  3. C \(11.2\)
  4. D \(9.5\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(9.5\)

Step-by-step Solution

Detailed explanation

Using\({P_1}{V_1} = {P_2}{V_2}\) \(\left( {{P_1}} \right)\frac{4}{3}\pi {r^3} = \left( {{P_2}} \right)\frac{4}{3}\pi \frac{{125{r^3}}}{{64}}\) \(\frac{{\rho g\left( {10} \right) + \rho gh}}{{\rho g\left( {10} \right)}} = \frac{{125}}{{64}}\) \(640 + 64\,h = 1250\)…
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