JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2023
- Hard
- Numerical
The distance between two consecutive points with phase difference of \(60^{\circ}\) in a wave of frequency \(500\,Hz\) is \(6.0\,m\). The velocity with which wave is traveling is \(.........km / s\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(18\)
Step-by-step Solution
Detailed explanation
\(\Delta \phi=\frac{2 \pi}{\lambda} \Delta x\)
\(\frac{\pi}{3}=\frac{2 \pi}{\lambda}(6 m )\)
\(\lambda=36\,m\)
\(V = f \lambda=(500\,Hz )(36\,m )\)
\(=18000\,m / s\)
\(=18\,km / s\)
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