JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
Two particles of equal mass \(\mathrm{m}\) have respective initial velocities \(u\hat{i}\) and \(u\left(\frac{\hat{\mathrm{i}}+ \hat{\mathrm{j}}}{2}\right) .\) They collide completely inelastically. The energy lost in the process is
- A \(\frac{3}{4} \mathrm{mu}^{2}\)
- B \(\frac{1}{8} \mathrm{mu}^{2}\)
- C \(\sqrt{\frac{2}{3}} \mathrm{mu}^{2}\)
- D \(\frac{1}{3} \mathrm{mu}^{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{8} \mathrm{mu}^{2}\)
Step-by-step Solution
Detailed explanation
From momentum conservation \(\operatorname{mu\hat{i}}+\operatorname{mu}\left(\frac{\hat{\mathrm{i}}+\hat{\mathrm{j}}}{2}\right)=(\mathrm{m}+\mathrm{m}) \overline{\mathrm{v}}\)…
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