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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2022
  • Medium
  • Numerical

If momentum of a body is increased by \(20 \%\), then its kinetic energy increases by\(....\%\)

Pick an option to check your answer.
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Answer & Solution

Correct Answer

(C) \(44\)

Step-by-step Solution

Detailed explanation

\(P ^{\prime}= P +\frac{20}{100} P =1.2 P\)

\(\%\) change in \(KE =\frac{ K ^{\prime}- K }{ K } \times 100\)

\(=\left(\frac{\frac{ P ^{2}}{2 m }-\frac{ P ^{2}}{2 m }}{\frac{ P ^{2}}{2 m }}\right) \times 100\)

\(= {\left[(1.2)^{2}-1\right] \times 100 }\)

\(= 44\%\)

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