JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2022
- Hard
- MCQ
As per the given figure, two blocks each of mass \(250\,g\) are connected to a spring of spring constant \(2\,Nm ^{-1}\). If both are given velocity \(V\) in opposite directions, then maximum elongation of the spring is:

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\frac{ V }{2}\)
Step-by-step Solution
Detailed explanation
using energy conservation
\(\frac{1}{2} mv ^{2} \times 2=\frac{1}{2} kx ^{2}\)
\(\frac{1}{4} v ^{2}=\frac{1}{2} \times 2 \times x ^{2}\)
\(x =\frac{ v }{2}\)
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