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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2022
  • Hard
  • MCQ

As per the given figure, two blocks each of mass \(250\,g\) are connected to a spring of spring constant \(2\,Nm ^{-1}\). If both are given velocity \(V\) in opposite directions, then maximum elongation of the spring is:

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Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{ V }{2}\)

Step-by-step Solution

Detailed explanation

using energy conservation

\(\frac{1}{2} mv ^{2} \times 2=\frac{1}{2} kx ^{2}\)

\(\frac{1}{4} v ^{2}=\frac{1}{2} \times 2 \times x ^{2}\)

\(x =\frac{ v }{2}\)

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