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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2021
  • Hard
  • Numerical

A balloon was moving upwards with a uniform velocity of \(10\, {m} / {s}\). An object of finite mass is dropped from the balloon when it was at a height of \(75\, {m}\) from the ground level. The height of the balloon from the ground when object strikes the ground was around.(In \({m}\)) (Takes the value of \(g\) as \(10 \,{m} / {s}^{2}\) )

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Answer & Solution

Correct Answer

(A) \(125\)

Step-by-step Solution

Detailed explanation

\(S=u t+\frac{1}{2} a t^2\)

\(-75=+10 t+\frac{1}{2}(-10) t^2\)

\(\Rightarrow t=5 sec\)

Object takes \(t=5 s\) to fall on ground

Height of balloon from ground

\(H=75+u t\)

\(H=75+10 \times 5=125 m\)

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