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JEE Mains · Physics · STD 12 -6. Electromagnetic induction

A \(20\,cm\) long metallic rod is rotated with \(210\,rpm\) about an axis normal to the rod passing through its one end. The order end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field \(0.2\,T\) parallel to the axis exists everywhere. The emf developed between the centre and the ring is \(.......\,mV\).Take \(\pi=\frac{22}{7}\)

  1. A \(88\)
  2. B \(66\)
  3. C \(55\)
  4. D \(44\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(88\)

Step-by-step Solution

Detailed explanation

Here \(\omega=210\,rpm\) \(=210 \times \frac{2 \pi}{60}\,rad / s\) \(\Rightarrow \omega=7 \pi\,rad / s\) \(\ell=0.2\,w\) \(B =0.2\,T\) \(\text { emf developed across rod is }=\frac{1}{2} B \omega \ell^2\) \(\frac{1}{2} \times 0.2 \times 7 \pi \times(0.2)^2\) \(=88\,mV\)
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