ExamBro
ExamBro
JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2023
  • Medium
  • Numerical

A \(20\,cm\) long metallic rod is rotated with \(210\,rpm\) about an axis normal to the rod passing through its one end. The order end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field \(0.2\,T\) parallel to the axis exists everywhere. The emf developed between the centre and the ring is \(.......\,mV\).Take \(\pi=\frac{22}{7}\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(88\)

Step-by-step Solution

Detailed explanation

Here \(\omega=210\,rpm\)

\(=210 \times \frac{2 \pi}{60}\,rad / s\)

\(\Rightarrow \omega=7 \pi\,rad / s\)

\(\ell=0.2\,w\)

\(B =0.2\,T\)

\(\text { emf developed across rod is }=\frac{1}{2} B \omega \ell^2\)

\(\frac{1}{2} \times 0.2 \times 7 \pi \times(0.2)^2\)

\(=88\,mV\)

Same subject
Explore more questions on app