JEE Mains · Physics · STD 11- 8. mechanical properties of solids
The Young's modulus of a steel wire of length \(6\,m\) and cross-sectional area \(3\,mm ^2\), is \(2 \times 11^{11}\,N / m ^2\). The wire is suspended from its support on a given planet. A block of mass \(4\,kg\) is attached to the free end of the wire. The acceleration due to gravity on the planet is \(\frac{1}{4}\) of its value on the earth. The elongation of wire is (Take \(g\) on the earth \(=10\) \(\left.m / s ^2\right):\)
- A \(1\,cm\)
- B \(1\,mm\)
- C \(0.1\,mm\)
- D \(0.1\,cm\)
Answer & Solution
Correct Answer
(C) \(0.1\,mm\)
Step-by-step Solution
Detailed explanation
\(\text { Tension }( F )= mg\) \(=4 \times \frac{10}{4}=10\,N\) \(\Delta L =\frac{ FL }{ AY }\) \(=\frac{10 \times 6}{3 \times 10^{-6} \times 2 \times 10^{11}}\) \(=10^{-4}\,m =0.1\,mm\)
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