JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2025
- Easy
- Numerical
A container of fixed volume contains a gas at \(27^{\circ} \mathrm{C}\). To double the pressure of the gas, the temperature of gas should be raised to ______ \({ }^{\circ} \mathrm{C}\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) 327
Step-by-step Solution
Detailed explanation
\(\begin{aligned} V & =\text { constant } \\ \frac{P_1}{T_1} & =\frac{P_2}{T_2} \\ P_2 & =2 P_1 \\ T_2 & =2 T_1 \\ & =2 \times 300=600 \mathrm{~K} \\ \therefore T_2 & =327^{\circ} \mathrm{C}\end{aligned}\)
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