JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2021
- Hard
- MCQ
Two ions of masses \(4 \,{amu}\) and \(16\, amu\) have charges \(+2 {e}\) and \(+3 {e}\) respectively. These ions pass through the region of constant perpendicular magnetic field. The kinetic energy of both ions is same. Then :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) lighter ion will be deflected more than heavier ion
Step-by-step Solution
Detailed explanation
\({r}=\frac{{P}}{{qB}}=\frac{\sqrt{2 {mk}}}{{qB}}\)
Given they have same kinetic energy
\({r} \propto \frac{\sqrt{{m}}}{{q}}\)
\(\frac{{r}_{1}}{{T}_{2}}=\frac{\sqrt{4}}{2} \times \frac{3}{\sqrt{16}}=\frac{3}{4}\)
\({I}_{2}=\frac{4 {r}_{1}}{3}\left[{r}_{2}\right.\) is for hearier ion and \({r}_{1}\) is for lighter ion)
\(\sin \theta=\frac{{d}}{{R}}\)
\(\theta \rightarrow\) Deflection
\(\theta \propto \frac{1}{{R}}\)
\(({R} \rightarrow\) Radius of path)
\(\because {R}_{2}>{R}_{1} \Rightarrow \theta_{2}<\theta_{1}\)
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