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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2021
  • Hard
  • MCQ

Two ions of masses \(4 \,{amu}\) and \(16\, amu\) have charges \(+2 {e}\) and \(+3 {e}\) respectively. These ions pass through the region of constant perpendicular magnetic field. The kinetic energy of both ions is same. Then :

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Answer & Solution

Correct Answer

(B) lighter ion will be deflected more than heavier ion

Step-by-step Solution

Detailed explanation

\({r}=\frac{{P}}{{qB}}=\frac{\sqrt{2 {mk}}}{{qB}}\)

Given they have same kinetic energy

\({r} \propto \frac{\sqrt{{m}}}{{q}}\)

\(\frac{{r}_{1}}{{T}_{2}}=\frac{\sqrt{4}}{2} \times \frac{3}{\sqrt{16}}=\frac{3}{4}\)

\({I}_{2}=\frac{4 {r}_{1}}{3}\left[{r}_{2}\right.\) is for hearier ion and \({r}_{1}\) is for lighter ion)

\(\sin \theta=\frac{{d}}{{R}}\)

\(\theta \rightarrow\) Deflection

\(\theta \propto \frac{1}{{R}}\)

\(({R} \rightarrow\) Radius of path)

\(\because {R}_{2}>{R}_{1} \Rightarrow \theta_{2}<\theta_{1}\)

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