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JEE Mains · Physics · STD 11 - 3.1 vectors

Vectors \(a \hat{i}+b \hat{j}+\hat{k}\) and \(2 \hat{i}-3 \hat{j}+4 \hat{k}\) are perpendicular to each other when \(3 a+2 b=7\), the ratio of a to \(b\) is \(\frac{x}{2}\). The value of \(x\) is \(..............\)

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

For two perpendicular vectors \((a \hat{i}+b \hat{j}+\hat{k}) \cdot(2 \hat{i}-3 \hat{j}+4 \hat{k})=0\) \(2 a-3 b+4=0\) On solving, \(2 a-3 b=-4\) Also given \(3 a+2 b=7\) We get \(a =1, b =2\) \(\frac{ a }{ b }=\frac{ x }{2} \Rightarrow x =\frac{2 a }{ b }=\frac{2 \times 1}{2}\)…
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