JEE Mains · Physics · STD 11 - Vectors
- JEE Mains 2023
- Hard
- Numerical
Vectors \(a \hat{i}+b \hat{j}+\hat{k}\) and \(2 \hat{i}-3 \hat{j}+4 \hat{k}\) are perpendicular to each other when \(3 a+2 b=7\), the ratio of a to \(b\) is \(\frac{x}{2}\). The value of \(x\) is \(..............\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
For two perpendicular vectors
\((a \hat{i}+b \hat{j}+\hat{k}) \cdot(2 \hat{i}-3 \hat{j}+4 \hat{k})=0\)
\(2 a-3 b+4=0\)
On solving, \(2 a-3 b=-4\)
Also given
\(3 a+2 b=7\)
We get \(a =1, b =2\)
\(\frac{ a }{ b }=\frac{ x }{2} \Rightarrow x =\frac{2 a }{ b }=\frac{2 \times 1}{2}\)
\(\Rightarrow x =1\)
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