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JEE Mains · Physics · STD 11 - Vectors
  • JEE Mains 2023
  • Hard
  • Numerical

Vectors \(a \hat{i}+b \hat{j}+\hat{k}\) and \(2 \hat{i}-3 \hat{j}+4 \hat{k}\) are perpendicular to each other when \(3 a+2 b=7\), the ratio of a to \(b\) is \(\frac{x}{2}\). The value of \(x\) is \(..............\)

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Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

For two perpendicular vectors

\((a \hat{i}+b \hat{j}+\hat{k}) \cdot(2 \hat{i}-3 \hat{j}+4 \hat{k})=0\)

\(2 a-3 b+4=0\)

On solving, \(2 a-3 b=-4\)

Also given

\(3 a+2 b=7\)

We get \(a =1, b =2\)

\(\frac{ a }{ b }=\frac{ x }{2} \Rightarrow x =\frac{2 a }{ b }=\frac{2 \times 1}{2}\)

\(\Rightarrow x =1\)

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