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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics

The truth table for the circuit given in the fig is

  1. A \( {\begin{array}{*{20}{c}}
    A&B&Y\\
    0&0&1\\
    0&1&0\\
    1&0&0\\
    1&1&0
    \end{array}} \)
  2. B \( {\begin{array}{*{20}{c}}
    A&B&Y\\
    0&0&0\\
    0&1&0\\
    1&0&1\\
    1&1&1
    \end{array}}\)
  3. C \( {\begin{array}{*{20}{c}}
    A&B&Y\\
    0&0&1\\
    0&1&1\\
    1&0&1\\
    1&1&1
    \end{array}}\)
  4. D \( {\begin{array}{*{20}{c}}
    A&B&Y\\
    0&0&1\\
    0&1&1\\
    1&0&0\\
    1&1&0
    \end{array}} \)
Verified Solution

Answer & Solution

Correct Answer

(D) \( {\begin{array}{*{20}{c}}
A&B&Y\\
0&0&1\\
0&1&1\\
1&0&0\\
1&1&0
\end{array}} \)

Step-by-step Solution

Detailed explanation

\(C=A+B\) and \(y=\overline{A . C}\)…
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