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JEE Mains · Physics · STD 11 - 11. thermodynamics
Given that \(1\,g\) of water in liquid phase has volume \(1\,cm^3\) and in vapour phase \(1671\, cm^3\) at atmospheric pressure and the latent heat of vaporization of water is \(2256\,J/g;\) the change in the internal energy in joules for \(1\,g\) of water at \(373\,K\) when it changes from liquid phase to vapour phase at the same temperature is ....... \(J\)
- A \(2256\)
- B \(167\)
- C \(2089\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(2089\)
Step-by-step Solution
Detailed explanation
\(W = P\left( {dV} \right)\)\( = 0.01 \times {10^5}\left( {1671 - 1} \right) \times {10^{ - 6}} = 167\,J\) \(Q = \Delta U + W\) \(\Delta U = Q - W = mL - 167\)\( = 2256 - 167 = 2089\,J\)
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