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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2023
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  • MCQ

A sample of gas at temperature \(T\) is adiabatically expanded to double its volume. The work done by the gas in the process is \(\left(\right.\) given, \(\left.\gamma=\frac{3}{2}\right)\) :

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Correct Answer

(D) \(W=R T[2-\sqrt{2}]\)

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Detailed explanation

\(T_1 V_1^{\gamma-1}=T_2 V_2^{\gamma-1}\)

\(T V^{1 / 2}=T_2(2 V)^{1 / 2}\)

\(T_2=\frac{T}{\sqrt{2}}\)

\(W=\frac{R\left(T_1-T_2\right)}{\gamma-1}=\frac{R\left(T-\frac{T}{\sqrt{2}}\right)}{\frac{1}{2}}=R T(2-\sqrt{2})\)

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