JEE Mains · Physics · STD 11 - 11. thermodynamics
For the given cyclic process \(CAB\) as shown for a gas, the work done is ..... \(J\)
- A \(30\)
- B \(10\)
- C \(1\)
- D \(5\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
Work done \(=\) Area of loop \(= \frac{1}{2} (4) (5)\) \(= 10\, J\)
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