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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2019
  • Easy
  • Numerical

For the given cyclic process \(CAB\) as shown for a gas, the work done is ..... \(J\)

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Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

Work done \(=\) Area of loop
                   \(= \frac{1}{2} (4) (5)\)
                   \(= 10\, J\)
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