JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2019
- Easy
- Numerical
For the given cyclic process \(CAB\) as shown for a gas, the work done is ..... \(J\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
Work done \(=\) Area of loop
\(= \frac{1}{2} (4) (5)\)
\(= 10\, J\)
\(= \frac{1}{2} (4) (5)\)
\(= 10\, J\)
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