JEE Mains · Physics · STD 11 - 9.2 surface tension
Pressure inside two soap bubbles are \(1.01\) and \(1.02\) atmosphere, respectively. The ratio of their volumes is
- A \(8:1\)
- B \(0.8:1\)
- C \(2:1\)
- D \(4:1\)
Answer & Solution
Correct Answer
(A) \(8:1\)
Step-by-step Solution
Detailed explanation
\(\Delta P _{1}=0.01=4 T / R _{1} \quad \ldots . .(1)\) \(\Delta P _{2}=0.02=4 T / R _{2} \quad \ldots . .(2)\) Equation \((1)+(2)\) \(\frac{1}{2}=\frac{ R _{2}}{ R _{1}}\) \(R _{1}=2 R _{2}\) \(\frac{V_{1}}{V_{2}}=\frac{R_{1}^{3}}{R_{2}^{3}}=\frac{8 R_{2}^{3}}{R_{2}^{3}}=8\)
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