JEE Mains · Physics · STD 12 -7. Alternating current
For a given series \(LCR\) circuit it is found that maximum current is drawn when value of variable capacitance is \(2.5 \mathrm{nF}\). If resistance of \(200 \Omega\) and \(100 \mathrm{mH}\) inductor is being used in the given circuit. The frequency of ac source is _______ \(\times 10^3 \mathrm{~Hz}\). (given \(\pi^2=10\) )
- A \(9\)
- B \(10\)
- C \(11\)
- D \(12\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
for maximum current, circuit must be in resonance \(\mathrm{f}_0=\frac{1}{2 \pi \sqrt{\mathrm{L} \times \mathrm{C}}}\) \(\mathrm{f}_0=\frac{1}{2 \pi \sqrt{100 \times 10^{-3} \times 2.5 \times 10^{-9}}}\) \(=\frac{1}{2 \pi \sqrt{25 \times 10^{-11}}}\)…
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