JEE Mains · Physics · STD 11 - 7. gravitation
If \(V\) is the gravitational potential due to sphere of uniform density on it's surface, then it's value at the center of sphere will be:-
- A \(\frac{3 V }{2}\)
- B \(V\)
- C \(\frac{4}{3} V\)
- D \(\frac{ V }{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{3 V }{2}\)
Step-by-step Solution
Detailed explanation
\(V =\frac{ GM }{2 R ^3}\left(3 R ^2- r ^2\right) \text { at } r=R \Rightarrow V=\left(\frac{ GM }{ R }\right)\) \(\text { at } r =0, V _0=\frac{3 GM }{2 R }=\left(\frac{3 V }{2}\right)\)
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