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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2023
  • Hard
  • MCQ

If \(V\) is the gravitational potential due to sphere of uniform density on it's surface, then it's value at the center of sphere will be:-

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Answer & Solution

Correct Answer

(A) \(\frac{3 V }{2}\)

Step-by-step Solution

Detailed explanation

\(V =\frac{ GM }{2 R ^3}\left(3 R ^2- r ^2\right) \text { at } r=R \Rightarrow V=\left(\frac{ GM }{ R }\right)\)

\(\text { at } r =0, V _0=\frac{3 GM }{2 R }=\left(\frac{3 V }{2}\right)\)

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