JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
For a free body diagram shown in the figure, the four forces are applied in the ' \(x\) ' and ' \(y\) ' directions. What additional force must be applied and at what angle with positive \(x\)-axis so that the net acceleration of body is zero?
- A \(\sqrt{2} N , 45^{\circ}\)
- B \(\sqrt{2} N , 135^{\circ}\)
- C \(\frac{2}{\sqrt{3}} N , 30^{\circ}\)
- D \(2 N , 45^{\circ}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{2} N , 45^{\circ}\)
Step-by-step Solution
Detailed explanation
Let addition force required is \(=\overrightarrow{ F }\) \(\overrightarrow{ F }+5 \hat{ i }-6 \hat{ i }+7 \hat{ j }-8 \hat{ j }=0\) \(\overrightarrow{ F }=\hat{ i }+\hat{ j },|\overrightarrow{ F }|=\sqrt{2}\) Angle with X-axis:…
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