JEE Mains · Physics · STD 12 - 12. atoms
A photon is emitted in transition from \(n =4\) to \(n =1\) level in hydrogen atom. The corresponding wavelength for this transition is \(.........\,nm\) \(\text { (given, } h =4 \times 10^{-15} eVs \text { ) : }\)
- A \(94.1\)
- B \(941\)
- C \(97.4\)
- D \(99.3\)
Answer & Solution
Correct Answer
(A) \(94.1\)
Step-by-step Solution
Detailed explanation
\(\frac{ hc }{\lambda}=\left[1-\frac{1}{16}\right](13.6\,eV )\) So, \(\lambda=94.1\,nm\)
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