JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
An object of mass \(5\, kg\) is thrown vertically upwards from the ground. The air resistance produces a constant retarding force of \(10\, N\) throughout the motion. The ratio of time of ascent to the time of descent will be equal to \(\left[\right.\)Use \(g =10 \,ms ^{-2}]\)
- A \(1: 1\)
- B \(\sqrt{2}: \sqrt{3}\)
- C \(\sqrt{3}: \sqrt{2}\)
- D \(2: 3\)
Answer & Solution
Correct Answer
(B) \(\sqrt{2}: \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(6\, t_{1}^{2}=4\, t_{2}^{2}\)
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