JEE Mains · Physics · STD 12 -7. Alternating current
A sinusoidal voltage \(V(t) = 100\,sin\,(500t)\) is applied across a pure inductance of \(L = 0.02\,H.\) The current through the coil is
- A \(10\,cos\,(500t)\)
- B \(-10\,cos\,(500t)\)
- C \(10\,sin\,(500t)\)
- D \(-10\,sin\,(500t)\)
Answer & Solution
Correct Answer
(B) \(-10\,cos\,(500t)\)
Step-by-step Solution
Detailed explanation
In a pure inductive circuit current always lags behind the emf by \(\frac{\pi}{2}\) If \(v(t)=v_{0} \sin \omega t\) then \(\mathrm{I}=\mathrm{I}_{0} \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right)\) Now, given \(v(t)=100 \sin (500 \,t)\) and…
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