ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2019
  • Hard
  • MCQ

Find the magnetic field at point \(P\) due to a straight line segment \(AB\) of length \(6\, cm\) carrying a current of \(5\, A\). (See figure) \((\mu _0 = 4p\times10^{-7}\, N-A^{-2})\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(1.5\times10^{-5}\, T\)

Step-by-step Solution

Detailed explanation

\(B=\frac{\mu_{0} I}{4 \pi d} 2 \sin \theta\)

\(d=4\, \mathrm{cm}\)

\(\sin \theta=\frac{3}{5}\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app