JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2019
- Hard
- MCQ
Find the magnetic field at point \(P\) due to a straight line segment \(AB\) of length \(6\, cm\) carrying a current of \(5\, A\). (See figure) \((\mu _0 = 4p\times10^{-7}\, N-A^{-2})\)

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Answer & Solution
Correct Answer
(D) \(1.5\times10^{-5}\, T\)
Step-by-step Solution
Detailed explanation
\(B=\frac{\mu_{0} I}{4 \pi d} 2 \sin \theta\)
\(d=4\, \mathrm{cm}\)
\(\sin \theta=\frac{3}{5}\)
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