JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Find the magnetic field at point \(P\) due to a straight line segment \(AB\) of length \(6\, cm\) carrying a current of \(5\, A\). (See figure) \((\mu _0 = 4p\times10^{-7}\, N-A^{-2})\)
- A \(2.0\times10^{-5}\, T\)
- B \(3.0\times10^{-5}\, T\)
- C \(2.5\times10^{-5}\, T\)
- D \(1.5\times10^{-5}\, T\)
Answer & Solution
Correct Answer
(D) \(1.5\times10^{-5}\, T\)
Step-by-step Solution
Detailed explanation
\(B=\frac{\mu_{0} I}{4 \pi d} 2 \sin \theta\) \(d=4\, \mathrm{cm}\) \(\sin \theta=\frac{3}{5}\)
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