JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Two charges of \(5 Q\) and \(-2 Q\) are situated at the points \((3 a, 0)\) and \((-5 a, 0)\) respectively. The electric flux through a sphere of radius \(4a\) having center at origin is
- A \(\frac{2 Q}{\varepsilon_0}\)
- B \(\frac{5 \mathrm{Q}}{\varepsilon_0}\)
- C \(\frac{7 Q}{\varepsilon_0}\)
- D \(\frac{3 Q}{\varepsilon_0}\)
Answer & Solution
Correct Answer
(B) \(\frac{5 \mathrm{Q}}{\varepsilon_0}\)
Step-by-step Solution
Detailed explanation
\(5 \mathrm{Q}\) charge is inside the spherical region flux through sphere \(=\frac{5 \mathrm{Q}}{\varepsilon_0}\)
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