JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
The top of a water tank is open to air and its water level is maintained. It is giving out \(0.74\,m^3\) water per minute through a circular opening of \(2\,cm\) radius in its wall. The depth of the centre of the opening from the level of water in the tank is close to........ \(m\)
- A \(6.0\)
- B \(4.8\)
- C \(9.6\)
- D \(2.9\)
Answer & Solution
Correct Answer
(B) \(4.8\)
Step-by-step Solution
Detailed explanation
\(\frac{{dv}}{{dt}} = Av \Rightarrow \frac{{dv}}{{dt}} = A\sqrt {2gh} \) \( \Rightarrow \frac{{0.74}}{{60}} = \left( {3.14} \right){\left( {\frac{2}{{100}}} \right)^2}\sqrt {2\left( {9.8} \right)h} \) \( \Rightarrow h = 4.92\,m\)
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