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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2024
  • Hard
  • Numerical

Two wavelengths \(\lambda_1\) and \(\lambda_2\) are used in Young's double slit experiment \(\lambda_1=450 \mathrm{~nm}\) and \(\lambda_2=650 \mathrm{~nm}\). The minimum order of fringe produced by \(\lambda_2\) which overlaps with the fringe produced by \(\lambda_1\) is \(n\). The value of \(n\) is _________.

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Answer & Solution

Correct Answer

(C) \(9\)

Step-by-step Solution

Detailed explanation

\(\mathrm{n}_2 \lambda_2=\mathrm{n}_1 \lambda_1\)

\(\frac{\mathrm{n}_2}{\mathrm{n}_1}=\frac{\lambda_1}{\lambda_2}=\frac{450}{650}=\frac{9}{13}\)

\(\mathrm{n}_2=9\)

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