JEE Mains · Physics · STD 12 - 10. Wave optics
Two wavelengths \(\lambda_1\) and \(\lambda_2\) are used in Young's double slit experiment \(\lambda_1=450 \mathrm{~nm}\) and \(\lambda_2=650 \mathrm{~nm}\). The minimum order of fringe produced by \(\lambda_2\) which overlaps with the fringe produced by \(\lambda_1\) is \(n\). The value of \(n\) is _________.
- A \(5\)
- B \(8\)
- C \(9\)
- D \(10\)
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}_2 \lambda_2=\mathrm{n}_1 \lambda_1\) \(\frac{\mathrm{n}_2}{\mathrm{n}_1}=\frac{\lambda_1}{\lambda_2}=\frac{450}{650}=\frac{9}{13}\) \(\mathrm{n}_2=9\)
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