JEE Mains · Physics · STD 12 - 12. atoms
During the transition of electron from state A to state C of a Bohr atom, the wavelength of emitted radiation is \(2000 Å\) and it becomes \(6000 Å\) when the electron jumps from state B to state C. Then the wavelength of the radiation emitted during the transition of electrons from state A to state B is _______.
- A \(4000 Å\)
- B \(2000 Å\)
- C \(3000 Å\)
- D \(6000 Å\)
Answer & Solution
Correct Answer
(C) \(3000 Å\)
Step-by-step Solution
Detailed explanation
\(\frac{h c}{\lambda_1}=E_0 z^2\left(\frac{1}{n_c^2}-\frac{1}{n_A^2}\right)\) ....(i) And \(\frac{h c}{\lambda_2}=E_0 z^2\left(\frac{1}{n_c^2}-\frac{1}{n_B^2}\right)\) So for \(A\) and \(B\) ....(ii) \(\frac{h c}{\lambda_3}=E_0 z^2\left(\frac{1}{n_B^2}-\frac{1}{n_A^2}\right)\)…
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