JEE Mains · Physics · STD 12 - 13. Nuclei
The radius of \(R\) of a nucleus of mass number \(A\) can be estimated by the formula \(R =\left(1.3 \times 10^{-15}\right) A ^{1 / 3}\, m .\) It follows that the mass density of a nucleus is of the order of \(\left( M _{\text {prot. }} \cong M _{\text {neut. }}=1.67 \times 10^{-27} kg \right)\)
- A \(10^{24} \;kg m ^{-3}\)
- B \(10^{3} \;kg m ^{-3}\)
- C \(10^{17} \;kg m ^{-3}\)
- D \(10^{10} \;kg m ^{-3}\)
Answer & Solution
Correct Answer
(C) \(10^{17} \;kg m ^{-3}\)
Step-by-step Solution
Detailed explanation
\(\rho_{\text {nucleus }}=\frac{\text { mass }}{\text { volume }}=\frac{A}{(4 / 3) \pi r_{0}^{3} A}=\frac{3}{4 \pi r_{0}^{3}}=2.3 \times 10^{17} kg / m^{3}\)
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