JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A thin convex lens made from crown glass \(\left( {\mu = \frac{3}{2}} \right)\) has focal length \(f\). When it is measured in two different liquids having refractive indices \(\frac{4}{3}\) and \(\frac{5}{3}\) it has the focal lengths \(f_1\) and \(f_2\) respectively. The correct relation between the focal lengths is:
- A \(f_1 > f \) and \(f_2\) becomes negative
- B \(f_2 > f\) and \( f_1\) becomes negative
- C \(f_1\) and \(f_2\) both becomes negative
- D \(f_1=f_2 < f\)
Answer & Solution
Correct Answer
(A) \(f_1 > f \) and \(f_2\) becomes negative
Step-by-step Solution
Detailed explanation
By Lens maker's formula for convex lens \(\frac{1}{f}=\left(\frac{\mu}{\mu_{L}}-1\right)\left(\frac{2}{R}\right)\) for, \(\mu_{L_{1}}=\frac{4}{3}, f_{1}=4 R\) for \(\mu_{L_{2}}=\frac{5}{3}, f_{2}=-5 R\) \(\Rightarrow f_{2}=(-) \mathrm{ve}\)
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