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JEE Mains · Physics · STD 11 - 13. oscillations

Consider two identical springs each of spring constant \(k\) and negligible mass compared to the mass \(M\) as shown. Fig. \(1\) shows one of them and Fig. \(2\) shows their series combination. The ratios of time period of oscillation of the two \(SHM\) is \(\frac{ T _{ b }}{ T _{ a }}=\sqrt{ x },\) where value of \(x\) is (Round off to the Nearest Integer)

  1. A \(3\)
  2. B \(2\)
  3. C \(6\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(T _{ a }=2 \pi \sqrt{\frac{ M }{ K }}\) \(T _{ b }=2 \pi \sqrt{\frac{ M }{ K / 2}}\) \(\frac{ T _{ b }}{ T _{ a }}=\sqrt{2}=\sqrt{ x }\) \(\Rightarrow x =2\)
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