JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2019
- Hard
- MCQ
Consider the \(LR\) circuit shown in the figure. If the switch \(S\) is closed at \(t = 0\) then the amount of charge that passes through the battery between \(t = 0\) and \(t = \frac{L}{R}\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\frac{{EL}}{{2.7{R^2}}}\)
Step-by-step Solution
Detailed explanation
\(q=\int 1 d t\)
\(\mathrm{q}=\int_{0}^{\mathrm{L} R} \frac{\mathrm{E}}{\mathrm{R}}\left[1-\mathrm{e}^{\frac{-\mathrm{Rt}}{\mathrm{L}}}\right] \mathrm{dt}\)
\(\mathrm{q}=\frac{\mathrm{EL}}{\mathrm{R}^{2}} \frac{1}{\mathrm{e}} \quad ; \quad \mathrm{q}=\frac{\mathrm{EL}}{2.7 \mathrm{R}^{2}}\)
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