JEE Mains · Physics · STD 12 -7. Alternating current
Consider the \(LR\) circuit shown in the figure. If the switch \(S\) is closed at \(t = 0\) then the amount of charge that passes through the battery between \(t = 0\) and \(t = \frac{L}{R}\) is
- A \(\frac{{EL}}{{7.3{R^2}}}\)
- B \(\frac{{EL}}{{2.7{R^2}}}\)
- C \(\frac{{7.3EL}}{{{R^2}}}\)
- D \(\frac{{2.7EL}}{{{R^2}}}\)
Answer & Solution
Correct Answer
(B) \(\frac{{EL}}{{2.7{R^2}}}\)
Step-by-step Solution
Detailed explanation
\(q=\int 1 d t\) \(\mathrm{q}=\int_{0}^{\mathrm{L} R} \frac{\mathrm{E}}{\mathrm{R}}\left[1-\mathrm{e}^{\frac{-\mathrm{Rt}}{\mathrm{L}}}\right] \mathrm{dt}\)…
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