JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2024
- Hard
- MCQ
Assuming the earth to be a sphere of uniform mass density, a body weighed \(300 \mathrm{~N}\) on the surface of earth. How much it would weigh at \(R / 4\) depth under surface of earth?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(225 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\(\text { At surface: } \mathrm{mg}=300 \mathrm{~N}\)
\(\mathrm{~m}=\frac{300}{\mathrm{~g}_{\mathrm{s}}}\)
\(\text { At Depth } \frac{R}{4}: g_d=g_s\left[1-\frac{d}{R}\right]\)
\(g_d=g_s\left[1-\frac{R}{4 R}\right]\)
\(\mathrm{g}_{\mathrm{d}}=\frac{3 \mathrm{~g}_{\mathrm{s}}}{4}\)
\(\text { weight at depth } \quad=\mathrm{m} \times \mathrm{g}_{\mathrm{d}}\)
\(=\mathrm{m} \times \frac{3 \mathrm{~g}_{\mathrm{s}}}{4}\)
\(=\frac{3}{4} \times 300\)
\(=225 \mathrm{~N}\)
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