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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2024
  • Hard
  • MCQ

Assuming the earth to be a sphere of uniform mass density, a body weighed \(300 \mathrm{~N}\) on the surface of earth. How much it would weigh at \(R / 4\) depth under surface of earth?

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Answer & Solution

Correct Answer

(D) \(225 \mathrm{~N}\)

Step-by-step Solution

Detailed explanation

\(\text { At surface: } \mathrm{mg}=300 \mathrm{~N}\)

\(\mathrm{~m}=\frac{300}{\mathrm{~g}_{\mathrm{s}}}\)

\(\text { At Depth } \frac{R}{4}: g_d=g_s\left[1-\frac{d}{R}\right]\)

\(g_d=g_s\left[1-\frac{R}{4 R}\right]\)

\(\mathrm{g}_{\mathrm{d}}=\frac{3 \mathrm{~g}_{\mathrm{s}}}{4}\)

\(\text { weight at depth } \quad=\mathrm{m} \times \mathrm{g}_{\mathrm{d}}\)

\(=\mathrm{m} \times \frac{3 \mathrm{~g}_{\mathrm{s}}}{4}\)

\(=\frac{3}{4} \times 300\)

\(=225 \mathrm{~N}\)

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