JEE Mains · Physics · STD 12 - 3. current electricity
A network of four resistances is connected to \(9\,V\) battery, as shown in figure. The magnitude of voltage difference between the points \(A\) and \(B\) is .......... \(V.\)
- A \(3\)
- B \(6\)
- C \(9\)
- D \(12\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
In the circuit \(I=\frac{9}{3}=3 A\) \(V_C-V_A=2 \times 1.5=3\) \(V_C-V_B=4 \times 1.5=6 \ldots \ldots\) \(Eq ^{ n }( II )- Eq ^{ n }( I )\) \(V _{ A }- V _{ B }=6-3=3 \text { Volt }\)
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