JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
In a screw gauge the zero of main scale reference line coincides with the fifth division of the circular scale when two studs are in contact. There are \(100\) divisions in circular scale and pitch of screw gauge is \(0.1\) mm. When diameter of a sphere is measured, the reading of main scale is \(5\) mm and \(50^{\text{th}}\) division of circular scale coincides with the reference line of main scale. The diameter of sphere is _______ mm.
- A \(5.045\)
- B \(5.055\)
- C \(5.450\)
- D \(5.550\)
Answer & Solution
Correct Answer
(A) \(5.045\)
Step-by-step Solution
Detailed explanation
Least count of the screw gauge is given by: \(\text{LC} = \dfrac{\text{Pitch}}{\text{Number of divisions on circular scale}}\) \(\text{LC} = \dfrac{0.1}{100} = 0.001 \text{ mm}\) When the two studs are in contact, the \(5^{\text{th}}\) division of the circular scale coincides…
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