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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

If the potential energy between two molecules is given by \(U =\frac{-A }{ r ^{6}}+\frac{ B }{ r ^{12}},\) then at equilibrium, separation between molecules, and the potential energy are

  1. A \(\left(\frac{ B }{ A }\right)^{1 / 6}, 0\)
  2. B \(\left(\frac{ B }{2 A }\right)^{1 / 6},-\frac{ A ^{2}}{2 B }\)
  3. C \(\left(\frac{2 B }{ A }\right)^{1 / 6},-\frac{ A ^{2}}{4 B }\)
  4. D \(\left(\frac{2 B }{ A }\right)^{1 / 6},-\frac{ A ^{2}}{2 B }\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left(\frac{2 B }{ A }\right)^{1 / 6},-\frac{ A ^{2}}{4 B }\)

Step-by-step Solution

Detailed explanation

\(U =\frac{- A }{ r ^{6}}+\frac{ B }{ r ^{12}}\) \(F =-\frac{ dU }{ dr }=-\left( A \left(-6 r ^{-7}\right)\right)+ B \left(-12 r ^{-13}\right)\) \(0=\frac{6 A }{ r ^{7}}-\frac{12 B }{ r ^{13}}\)…
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