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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2017
  • Hard
  • MCQ

The figure shows three circuits \(I, II\) and \(III\) which are connected to a \(3\,V\) battery. If the powers dissipated by the configurations \(I, II\) and \(III\) are \(P_1 , P_2\) and \(P_3\) respectively, then

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Answer & Solution

Correct Answer

(C) \(P_2 > P_1 > P_3\)

Step-by-step Solution

Detailed explanation

From the given circuit, net resistances \({{\rm{R}}_I} = 1\,\Omega ,{{\rm{R}}_{{\rm{II}}}} = 1/2\,\Omega ,{{\rm{R}}_{{\rm{III}}}} = 3/2\,\Omega \)

It is clear that \(\mathrm{R}_{3}>\mathrm{R}_{1}>\mathrm{R}_{2}\)

Hence, \({P_3} < {P_1} < {P_2}\)

As Power \((P)\) \(=\frac{\mathrm{V}^{2}}{\mathrm{R}} \Rightarrow \mathrm{P} \propto \frac{1}{\mathrm{R}}\)

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